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2b^2-34b-387=0
a = 2; b = -34; c = -387;
Δ = b2-4ac
Δ = -342-4·2·(-387)
Δ = 4252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4252}=\sqrt{4*1063}=\sqrt{4}*\sqrt{1063}=2\sqrt{1063}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{1063}}{2*2}=\frac{34-2\sqrt{1063}}{4} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{1063}}{2*2}=\frac{34+2\sqrt{1063}}{4} $
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